Well it all depends on how much overclocking your going to do.
First off we need to figure out how many watts of heat your processor
produces.
To find out what your processor produces use the chart below:
|
Intel Users |
| PIII
500-1 GHz users click here
(480k) page 47. |
| Celeron
users click here
(1.49 megs) page 56 and 57. |
|
AMD
Users |
| Athlon
users click here
(1.41) page 21. |
| Duron
users click here
(1.43 megs) page 19. |
Ok now that you have the maximum heat output
of your chip, use the formula (taken from overclockers.com) to figure out what
your overclocked CPU will produce:
Pnew = Pspec * (Fnew/Fspec) * (Vnew/Vspec)^2
-
Pnew = the new heat output in wattage
-
Pspec = the heat output specified by the manufacturer
-
Fnew = the new CPU Frequency
-
Fspec = the default CPU Frequency
-
Vnew = the new voltage setting
-
Vspec = the default voltage setting
So with that said lets say, I want to overclock a Celeron 600
to 900 at 1.75v:
32.58 = 15.8 x (900/600) x (1.75/1.5)^2
That means when I overclock a Celeron from 600
to 900 we increase the amount of heat produced from 15.8 watts to 32.58 watts,
which is 106.2% increase in the amount of heat produced. Note that this is only an estimate the
true heat output could be higher or lower.
Now to get any sort of benefit of using a peltier over an air-cooled system
(cooling below the ambient temperature) you have to double or more the amount of
watts that the CPU outputs. In
other words take the calculated Pnew and multiply it by two or more. So I would
need a 66+ watt peltier to cool the chip below the ambient temperature.
Note: You won’t always get the maximum wattage
out of you peltier so it is better to allow for more, plus you may always want
to overclock even more that what you though you wanted to...
So what does this mean for the CPU
temperature? Well here is a handy
formula from Toby at BxBoards to see how many
ºC a peltier will remove.
Delta T = (1 - (heat load/max cooling power))*max
temp difference
- Heat load = the heat output of the CPU in watts
- Max cooling power = the max heat rating your peltier can remove in watts
Max temp difference = the temperature difference of the hot
side of the peltier and the cold side in ºC
So lets say that our 66-watt peltier has a max temp difference of 70 ºC. So Delta T = (1-(32/66))* 70. Which give us a change of 36.0ºC, that
means this peltier will remove 36ºC from my chip!!! Ahh I can see it in your eyes you just
can’t wait to slap that bad boy on your chip can you? Well hold on, there is another area we
have to cover. With all this
cooling your peltier generates a lot of heat, I mean a lot of heat! Lets to a look at what you have to do to
cool this bad boy…
