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-- A Guide To Peltiers
-- Category: Guide
-- Posted by: winterstick
-- Posted on: 2001-01-13
-- Price: ~ $NA USD
-- Pages: 1 [ 2 ] 3 4 5 6 7 8 9 10 11 12 13
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Well it all depends on how much overclocking your going to do.  First off we need to figure out how many watts of heat your processor produces.  To find out what your processor produces use the chart below:

Intel Users

PIII 500-1 GHz users click here (480k) page 47.
Celeron users click here (1.49 megs) page 56 and 57.

AMD Users

Athlon users click here (1.41) page 21.
Duron users click here (1.43 megs) page 19.

   Ok now that you have the maximum heat output of your chip, use the formula (taken from overclockers.com) to figure out what your overclocked CPU will produce:

Pnew = Pspec * (Fnew/Fspec) * (Vnew/Vspec)^2

  • Pnew = the new heat output in wattage

  • Pspec = the heat output specified by the manufacturer

  • Fnew = the new CPU Frequency

  • Fspec = the default CPU Frequency

  • Vnew = the new voltage setting

  • Vspec = the default voltage setting

So with that said lets say, I want to overclock a Celeron 600 to 900 at 1.75v:

32.58 = 15.8 x (900/600) x (1.75/1.5)^2 

   That means when I overclock a Celeron from 600 to 900 we increase the amount of heat produced from 15.8 watts to 32.58 watts, which is 106.2% increase in the amount of heat produced.  Note that this is only an estimate the true heat output could be higher or lower. 

   Now to get any sort of benefit of using a peltier over an air-cooled system (cooling below the ambient temperature) you have to double or more the amount of watts that the CPU outputs.  In other words take the calculated Pnew and multiply it by two or more. So I would need a 66+ watt peltier to cool the chip below the ambient temperature.

   Note: You wont always get the maximum wattage out of you peltier so it is better to allow for more, plus you may always want to overclock even more that what you though you wanted to...

   So what does this mean for the CPU temperature?  Well here is a handy formula from Toby at BxBoards to see how many C a peltier will remove.

Delta T = (1 - (heat load/max cooling power))*max temp difference
  • Heat load = the heat output of the CPU in watts
  • Max cooling power = the max heat rating your peltier can remove in watts

Max temp difference = the temperature difference of the hot side of the peltier and the cold side in C 

   So lets say that our 66-watt peltier has a max temp difference of 70 C.  So Delta T = (1-(32/66))* 70.  Which give us a change of 36.0C, that means this peltier will remove 36C from my chip!!!  Ahh I can see it in your eyes you just cant wait to slap that bad boy on your chip can you?  Well hold on, there is another area we have to cover.  With all this cooling your peltier generates a lot of heat, I mean a lot of heat!  Lets to a look at what you have to do to cool this bad boy



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